If it is 2*( 4xy-7)
= 8xy -14
If it is (4xy-7)^2= (4xy-7)(4xy-7)= 16x^2y^2 - 28xy -28xy +49
= 16x^2y^2 - 56xy +49
2007-03-01 01:12:30
·
answer #1
·
answered by The exclamation mark 6
·
1⤊
0⤋
distribute the 2 to get 4xy(2) - 7(2) this equals 8xy - 14. that's as far as you can go
2007-03-01 01:10:16
·
answer #2
·
answered by metalluka 3
·
0⤊
0⤋
(4xy-7)2
I think you're asking for that number squared. (4xy-7)^2 (or the two is raised)
If so,
(4xy-7)^2 =
(4xy-7)(4xy-7) =
16x^2y2 - 56xy + 49
2007-03-01 01:14:06
·
answer #3
·
answered by Steve A 7
·
0⤊
0⤋
(4xy-7)2 = 8xy-14
or
x = 14/8y
x=7/4y
or
y14/8x
y=7/4x
2007-03-01 01:14:56
·
answer #4
·
answered by rA_0215 2
·
0⤊
1⤋
distribute the 2 into the equation to get:
8xy - 14.
but other than that not sure what you're looking for
Good luck.
2007-03-01 01:09:10
·
answer #5
·
answered by ClooneyIsAGenius 2
·
0⤊
0⤋
16x2y2 - 56xy + 49
2007-03-01 01:29:55
·
answer #6
·
answered by yash_slim_shady 2
·
0⤊
0⤋
8XY-14
2007-03-01 01:11:55
·
answer #7
·
answered by yogesh gulhania 2
·
0⤊
0⤋