The two beads are identical. Assume the mass is m and charge is q for both beads. The walls of the bowl are assumed frictionless and non-conducting. The beads repel each other and move up the walls to become distance R apart at equilibrium. What is the charge on each bead?
2007-03-01 00:54:12 · 2 answers · asked by metalluka 3 in Science & Mathematics ➔ Physics
So the bowl and radius are just red herrings? they do not add anything to the problem? i was thinking that you could somehow find the force due to gravity and normal force from the bowl to reduce the charge somehow.
2007-03-01 01:58:19 · update #1
The components of the repelling force and the gravitational force will be equal tangent to the wall at the equilibrium point.
2007-03-01 14:51:29 · answer #1 · answered by meg 7 · 0⤊ 0⤋
If the initial charge is 'q' on each bead then the charge on each bead is still 'q' even though they have repelled each other apart.
This is called Coloumns Law and has the equation-:
Force = q1 x q2 / 4 x pi x Epsilon0 x distance apart^2
2007-03-01 01:24:40 · answer #2 · answered by Doctor Q 6 · 0⤊ 0⤋