What will happen to the flow velocity of water in a pipe whose radius suddenly doubles?

Answer 1

The flow velocity will be reduced by 4 and the pressure will double.

It's all abouyt Bernoulli and conservation of energy ☺


Doug

Answer 2

Since water is incompressible, the total volume flow at any point in the pipe must be constant. The volumetric flow is V*A, where V is the flow velocity, and A the area of the pipe. When you double the radius of the pipe, the area increases by a factor of 4 (A=πr^2), therefore to maintain the same flow volume, V must decrease by the same factor.

Answer 3

the velocity of the water will be 1/4 becaused acc. to bernaullis theorem a1v1=a2v2 -------1where a is the area of the of the pipe and v is the velocity of liquidin it

the area is =∏r^2 as radius is doubled the area will be 4 times and thus acc. to eq. 1 the velocity will be reduced to 1/4

Answer 4

the speed of the water interior the pipe relies upon on the "head tension", accordingly if the suited is open, or vents to atmostphere, the "head-tension" is 10Feet, that gravity will exert a tension on the water. limiting the pipe diameter, or frictional losses WILL shrink the speed AND the quantity of water that flows. If, you like the comparable quantity of water to flow yet with much less speed, you should shrink the top-presure on the pass.....you may accomplish this by flowing down 5ft, right into a small(vented) conserving tank, then the OVERFLOW of this tank is piped down 5 greater feet(a step-result) . this way by various pipe length, you may supply the comparable quantity of water at decrease speed over the ten feet drop....