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how many days does it take the snail to reach 10 meters.?

2007-02-28 20:45:05 · 8 answers · asked by Anonymous in Science & Mathematics Mathematics

8 answers

1 day
lol

2007-02-28 20:49:36 · answer #1 · answered by twocenst 3 · 0 0

If it takes it a whole day to crawl up 5 metres and fall down 4 metres then it will take it 10 days to reach 10 metres.

If, on the other hand, it's a show-off speedy-Gonzalez type snail that can do the 5 up 4 down in an hour then it will take it 10 hours.

And so on...

Edit: Oh, I've got it now, why didn't I think of that, many thanks gauravgupta7000! But Jerry P also has a point about no velocity being stated... Duh, I feel silly now! But it's been good to learn a logic lesson.

2007-03-01 04:51:23 · answer #2 · answered by Anonymous · 0 0

On the 6th day, the snail will have reach 10th meter up the wall.
On the 1st day, the snail reached 1 meter.
2nd day = 2 meters
3rd day = 3 meters
4th day = 4 meters
5th day = 5 meters and on the
6th day, the snail crawls up a wall 5 meters which means that it had already reached the 10th meter.

2007-03-01 05:15:51 · answer #3 · answered by Harry Ian John 1 · 0 0

Since it goes up 5 meters and then falls down 4 meters, it's net climb is 1 metre/day.

So after the end of 4th day, it would have climbed till 4 meters.
Now on day 5, it again climbs till 9 metres, but again falls back and reached 5 metre level.

On day 6 however, it climbs up 5 meters - and hence reaches 10 metre mark! It wont fall down that time... Since he is able to cross the wall after that.

So snail takes only 6 days.

2007-03-01 05:08:59 · answer #4 · answered by Gaurav Gupta 1 · 1 0

6 days

2007-03-01 04:49:13 · answer #5 · answered by shilpu 2 · 0 0

6 days
The snail crawls up a net of 1 metre daily.So it should take 10 days.But on end of 5th day will be 5 metres up.So on 6th day it will reach 10m.

2007-03-01 05:01:14 · answer #6 · answered by know it 2 · 0 0

it would take 10 days 5-4=1 1x10=10

2007-03-01 04:56:11 · answer #7 · answered by Dave aka Spider Monkey 7 · 0 0

No velocity information is given in the problem, and as stated, it is not solvable.

2007-03-01 04:56:56 · answer #8 · answered by Jerry P 6 · 1 0

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