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I am new to chem and am struggling!
If I dissolve 39.998 grams of NaOH in 1 Liter of water. The formula of the dissociation of NaOH is NaOH(s) + H2O(l)--------> Na+(aq) + OH-(aq) Now how do I show the full steps of do this (using what eqautions) to obtain the Molarity-M?

2007-02-28 19:49:39 · 1 answers · asked by Gideon 1 in Science & Mathematics Chemistry

1 answers

39.998g of NaOH is the molecular weight of 1 mole NaOH.

If you dissolve this quantity in a liter ,you have 1 mole by liter anf it is a molar solutions

for the ions you see that 1 molecule NaOH gives 1 ion Na+ and 1 ion OH-. so ,the solution is also molar in Na+ and OH-

2007-02-28 21:12:23 · answer #1 · answered by maussy 7 · 0 0

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