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2007-02-28 19:31:35 · 2 answers · asked by unibloke1 1 in Science & Mathematics Chemistry

2 answers

If you mean how do you go about testing a particular compound for its solubility in water, you have to begin with a known quantity of water, and a known mass of your compound, and you have to record both the temperature of the water and the pressure of the container.

Add the compound to the water, and mix it into the water, and if it all disolves, you have to get more of the compound and keep on adding it, until you have undissolved compound at the bottom of your container. Then you keep on mixing the contents to keep on trying to get as much to dissolve into the water as possible. Sometimes this means to leave it mixing overnight.

When you have decided to stop mixing it, you again test the temperature and the pressure to ascertain that neither of those have changed, and then you filter out the undissolved compound.

Then, by subtracting the undissolved mass of compound from the amount you started with, you have the mass of compound that was dissolved into the water.

Then, you declare that amont of compound to be souluble into that amount of water, at that temperature and at that pressure.

If you didn't start out with exactly one liter of water, you will have to adjust the equasion for the proportion of the compound to dissolve into one liter.

2007-02-28 20:18:25 · answer #1 · answered by Robert G 5 · 0 0

The amount of solute that can be dissolved into a solution.

Like salt into water.

So it would be grams per liter or some similar measurement.

It depends on the solute/solution combination how you actually do the measuring.

2007-03-01 03:36:29 · answer #2 · answered by bourgoise_10o 5 · 0 0

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