Find the slope and the y-intercept of the line. -8x-9y=27?

Question

Find the slope and the y-intercept of the line. -8x-9y=27

The slope is________
the y-intercept is (0,___)

Answer 1

The slope is -8/9
the y-intercept is (0,-3)

You just need to move the -8x to the RHS, and divide to make the coefficient of y to 1.

y = -8x/9 - 3

Which is in y = mx + b form.

Answer 2

slope fomula is -a/b and then find a and b in your question which can be re written as 8x+9y=-27
then a= 9 and b= -8 then it gives slope as -9/8
for y intercept put z=x=0
then it gives
8(0)+9y= 27
9y= 27
y= 3
this may be the answer
plz check more

Answer 3

Put the equation into the slope-intercept form, i.e.
write the equation such that y should be on the left
hand side by itself, i.e. -9y = 8x + 27, i.e.
y = (-8/9)x + (-3).
Then slope is -8/9 and the y-intercept is -3.

Answer 4

9y = -8x -27
=>y = -8x/9 -3
This is in slope-intercept form
=> slope=-8/9 and y intercept = -3

Answer 5

Solve for y to change to y = mx + b format. Dividing by 9 yields => -(8/9)x-y = 3 So y = -(8/9)x-3 Therefore -8/9 is your slope and plugging x=0, gives you your y intercept of -3.

Answer 6

-8x -9y = 27
-9y = 8x + 27
y = (8/-9)x + (27/-9)
slope = -8/9
yint = -3

Answer 7

9y = - 8x - 27

y = (- 8/9).x - 3

slope is (-8/9)
y intercept is (0,- 3)

Answer 8

y = mx + b
slope = m

so if you rearrange the equation you would get (-8/9)x - 3 = y
so the slope is (-8/9)

the y-int is when you plug "0" in for the x-value to get (-3), so the y-int is at (0,-3)

Answer 9

-8/9
-3