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Let s equal { x > 0}. Prove S is bounded below and find inf [s]. Show S is unbounded above.

Need answers quick! Any help would be appreciated!

2007-02-28 18:01:58 · 5 answers · asked by jondavs9 1 in Education & Reference Homework Help

5 answers

Well, I don't know math, but ...
it seems to me the statement is "s equals something more than zero"
so it's bound at the bottom by zero but there is no upper limit...??

2007-02-28 18:15:49 · answer #1 · answered by and_y_knot 6 · 0 0

x> 0 implies that no value of x can exist below zero and zero itself is also excluded. Therefore zero constitutes the lower bundary of this Sum to infinity is infinity itself and hence it is not bounded on the upper end

2007-02-28 18:17:58 · answer #2 · answered by Anonymous · 0 0

oh its ummmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm i dnt know sorry search n look 4 help

2007-02-28 18:08:52 · answer #3 · answered by lala 1 · 0 0

sorry your question is not clear

2007-02-28 19:05:21 · answer #4 · answered by akhila k 3 · 0 0

i think ur question is not very clear....srry

2007-02-28 18:08:41 · answer #5 · answered by Anonymous · 0 0

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