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6 answers

The side facing the sun is around 250 degrees Fahrenheit.

The otherside, blocked from the sun, is around -250 degrees Fahrenheit.

Without the Ozone layer and the fullest advantages of Earth's electromagnetic feild, you are being bombarded with a greater humber of high energy particles than you would on Earth. This is called Solar Wind. The side of you reciving the wind is boiled, while the lee side is frozen.

If you don't believe me, check the surface tempature of Mercury, same side is always facing the sun. One side is extremely hot, the other extremely cold, even though it's right next to the Sun.

2007-02-28 17:44:44 · answer #1 · answered by socialdeevolution 4 · 0 0

it really is a confusing element... area *has* no temperature, in effortless words products do. So, once you're strolling by the air, it ought to sense chilly or warmth to you, yet it really is because the air molecules have a temperature. In area, interior the direct image voltaic, products can warmth as a lot as about 290 degrees fahrenheit, and also, in shadow, they could cool off to about 2 hundred degrees below 0. Now, it ought to't drop *a lot* more suitable than that, because there is warmth making it to the shadowed parts by the metallic of the station's pores and skin, and there is also warmth radiating up from the Earth.

2016-12-05 02:21:05 · answer #2 · answered by Anonymous · 0 0

Temperature implies a physical substance, so the space that's outside of the Space Station is sufficiently close to hard vacuum, that you cannot realistically measure its temperature.

A common saying is that a thermometer actually measures the temperature of itself, since heat transfer must be in equilibrium between the thermometer and the object whose temperature it is supposed to measure.

A perfect blackbody, say a flat plate facing the sun in Earth's orbit receives about 1366 W/m^2 of solar energy:
http://en.wikipedia.org/wiki/Solar_constant

It must radiate sufficient energy to arrive at a energy balance.into the 2.725 kelvin cosmic background:
http://en.wikipedia.org/wiki/Cosmic_microwave_background_radiation

Using the Stefan-Boltzmann law:
http://en.wikipedia.org/wiki/Stefan-Boltzmann_law we can equate the 1366 W/m^2 of incoming solar energy with some temperature at which a perfect blackbody would be in energy equilibrium. That temperature works out to be 331 K or about 58ºC, which is a bit warmish compared to the average temperature of Earth, but it's pretty darn close.

2007-02-28 18:23:54 · answer #3 · answered by arbiter007 6 · 0 0

the temperature does not remain fixed due to terrestrial body like asteriod which affects the temerature & so it is difficult to measure the temperature .

2007-02-28 18:12:13 · answer #4 · answered by manish p 1 · 0 0

My educated guess would be colder than a witches t*t.

2007-03-04 06:54:37 · answer #5 · answered by Anonymous · 0 0

very cold

2007-02-28 17:31:09 · answer #6 · answered by red12saleen 2 · 0 0

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