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How do you write the net ionic equation when sulfuric acid is neutralized by potassim hydroxide in aqueous solution

2007-02-28 16:41:57 · 1 answers · asked by ChristFirst00 2 in Science & Mathematics Chemistry

1 answers

first off you need to find out which of the molecules are strong electrolytes by looking in a textbook or the internet. if they are strong they will dissolve in an aqueous solution. after doing research i found that KOH is a weak electrolyte and insoluble whereas h2so4 is soluble...therefore....

KOH + H(+) + SO4(2-)------>K+ + SO4(2-) + H2O

if the ions are present on both sides of the equation then they are called spectator ions and can be crossed out because they don't take part in the reaction(just like spectators don't take part in a basketball game). so therefore we have our net ionic equation of....

KOH + H(+) ------>K(+) + H2O


ta da! hope this helps!

2007-02-28 17:00:19 · answer #1 · answered by Logan 4 · 0 0

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