Or, may you please help me prove this one?:
Given the square ABCD.
Construct AC.
Construct ray AT that bisects angle CAD.
Label the intersection of ray AT and DC at point I.
Construct the perpendicular bisector of AI called line F.
Label the intersection of line F and segment AC at point N.
Construct circle with center N that contains A.
Label the intersections of the circle and the square at points Y and G.
Construct YG.
Semicircle YIG is the req. construction.
2007-02-28
15:55:09
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2 answers
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asked by
tiff-fee-uh-nee. x_X
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