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a .005 kg bullet has a velocity of 500 meters per second when it hits a stationary 2.002 kg block of wood suspended by 2 ropes. the bullet imbeds itself in the block. (a) use the conservation of momentum to find v2, the velocity of the block and the bullet immediately after the impact. (b) what was the total kinetic energy immediately after the impact? (c) if all the kinetic energy was transferred to potential energy, mgh, how high did the block swing?

2007-02-28 15:14:10 · 1 answers · asked by mandy 1 in Science & Mathematics Physics

1 answers

www.xmission.com/~fractal/math/kp. This might help you . Good luck!

2007-02-28 15:37:10 · answer #1 · answered by eudaemon 4 · 0 0

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