Chemistry Help! Please?

Question

To what temperature must a 3.0 L container filled with 10.1 g of Kr be heated to obtain a pressure of 1.10 atm? Express your answer to the nearest degree Kelvin.
Please Explain

Answer 1

O.K. This sounds like the ideal gas law:

PV=nRT
P=Pressure, V=Volume, n=number of moles, R=constant, T=Temps (in kelvin)

///Convert grams to moles
(10.1g Kr)/(83.8 g/mol Kr)=.121mol Kr
///Plug into equation
(1.10atm)(3.0L)=(.121mol Kr)(.0821 L*atm/mol*K)(X)
///R is a constant, equal to .0821 for atmospheres
X= 333K