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A store is selling a sweater for $17.90. The regular price is $22.95. What percent of the regular price is the sweater on sale for?

Please if you find out the answer tell me how and why you did it. Please thanks.

2007-02-28 12:03:44 · 7 answers · asked by kittie_queen_95 1 in Education & Reference Homework Help

7 answers

i guess and checked, i did 28%=5.012 so 17.90+5.012=22.91 and that is as close as i could get it with out going over. I did it because u asked me to . i started out wiht like guessing and checking 10% but that was too low so 25% was closer and then i guess and checked each single percent after that. so i 28%

2007-02-28 12:12:56 · answer #1 · answered by Jen 3 · 0 0

I'm a tough shopper, and just looking at the price, I'd say 25% but that's guessing lol (still it gives you a guide).

Now to figure it out, you take the smaller figure and / it by the larger figure, as so:
17.90 / 22.95 = 0.78
And then x 100 to get the % = 78%
But that's 78% original, so 100% - 78% = 22% off

The formula:
smaller / larger = whatever
whatever x 100 = % Original
100% - % original = % off

The wanna make sure test:
22.95 x 0.78 = 17.90

That % original is not a real math term, it's just the terms I use.

2007-02-28 12:10:37 · answer #2 · answered by netthiefx 5 · 1 0

okay, so you know that the percent off times 22.95 is going to equal $17.90, so

(x)(22.95) = 17.90

So, first, divide by 22.95, and find that x = 0.78.

This does not mean, though, that the sweater is 78% off. You have to take 1 - 0.78, to get the actual sale price of 22%

2007-02-28 12:11:58 · answer #3 · answered by crzywriter 5 · 1 0

17.90/22.95=.78
.78 X 100= 78%
The sweater is on sale for 78% of the regular price.
(17.90 divided by 22.95 equals .78)

2007-02-28 12:17:48 · answer #4 · answered by mrsfloridalady 2 · 0 0

25%

2007-02-28 12:12:14 · answer #5 · answered by Anonymous · 0 0

22%

2007-02-28 12:14:17 · answer #6 · answered by cmhurley64 6 · 0 0

28.21% = (22.95-17.90)/17.90


check: 17.9 x 1.2821 = 22.95

2007-02-28 12:11:16 · answer #7 · answered by ad_sessionrd 2 · 0 2

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