which of the following is a balanced equation representing the decomposition of lead(IV) oxide?
a.PbO2--Pb+O2
b.Pb2O--2Pb+O
c.PbO--Pb+O2
d.PbO2--Pb+2O
2007-02-28 11:54:25 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
"A"
lead (IV) has a charge of 4+ and oxygen has a charge of 2-. The only reactant that has the correct combination of these two ions is letter A. It takes two oxygen ions to balance out the charge of one lead ion.
The products would be solid lead and oxygen gas. Oxygen gas is diatomic so it must be written as O2. Again letter A is the only answer written correctly.
2007-02-28 11:57:24 · answer #1 · answered by physandchemteach 7 · 1⤊ 0⤋
a
because Pb has a charge of 4 and O has a charge of 2, so you give O sub 4 and Pb sub 2 to balance out the compound, and then you may simplify that to PbO2.
that would then decompose to Pb and O2 (It is O2 because of some rule the "L" and H rule my teacher calls it)
haha this question was just on my test
2007-02-28 20:02:02 · answer #2 · answered by kay 2 · 0⤊ 0⤋
a
2007-02-28 19:57:16 · answer #3 · answered by mcollins123 2 · 1⤊ 0⤋