Please tell me how to do these?
How many moles of gaseous arsine (AsH3) occupy 0.601 L at STP?
mol
What is the density of gaseous arsine?
g/L
2007-02-28 09:21:59 · 5 answers · asked by ? 2 in Science & Mathematics ➔ Chemistry
this is quite simple since there at 22.4 L of all gases in one mole at STP.
0.601L AsH3/22.4 L (equals 0.0268moles)
to find density convert moles to grams then divide by liters
0.0268 moles*77.92 g AsH3 (77.92 is the molar mass of AsH3)
equals 2.0906 g AsH3.
2.0906 g/0.601 L
density equals 3.4786 g/L
2007-02-28 10:46:25 · answer #1 · answered by melovecheese1 2 · 0⤊ 0⤋
AsH3 is composed mainly of As and H x 3. Therefore there are 4 moles, As, H, H, H. the .601L at STP is 11...everyone knows that. Therefore...there is 15 moles.
Gaseous Arsinie has a density of 1.5/gprs.
2007-02-28 17:31:31 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Handy dandy fact # 1. At STP, 1 mole of anything occupies 22.4 liters. Now you can scale that down to your 0.6 liters:
1 mole/ 22.4 L = x mole / 0.6 L = 0.027 moles
Density depends on temp and pressure. Since handy dandy fact #1 tells us that 1 mole occupies 22.4 liters, we can figure out density by finding mole we of arsine. If I remember right, AsH3 is about 90 g/gmole, so density would be 90 g/ 22.4 L= 4.1 g/L approximately
2007-02-28 17:30:30 · answer #3 · answered by cattbarf 7 · 1⤊ 0⤋
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2007-02-28 17:31:09 · answer #4 · answered by bassdog65 4 · 0⤊ 0⤋
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2007-02-28 17:25:12 · answer #5 · answered by Anonymous · 0⤊ 1⤋