a)sodium carbonate decahydrate, Na2CO3 X 10H2O
b) nickel (II) iodide hexahydrate, Nil2 X 6H2O
c)ammonium hexacyanoferrate (III) trihydrate, (NH4)2Fe(CN)6 x 3H2O
d)aluminum bromide hexahydrate
2007-02-28 08:37:23 · 4 answers · asked by Lore 1 in Science & Mathematics ➔ Chemistry
Add the mass of the entire hydrate - including the water. Add the mass of the water only in each hydrate. Divide mass of water by mass of entire hydrate to get % water.
2007-02-28 08:48:32 · answer #1 · answered by physandchemteach 7 · 0⤊ 0⤋
I'll do the first one. The others are solved pretty much the same way. I don't have my periodic table for other than the lower elements.
This is a mass of water/mass of compound basis, so we only need to find the total compound weight and the total water weight. 10 H2O= 180 g/gmole
Na2CO3 = 2*22+12+48= 104 g/gmole
Percent water = 100 (180/(180+104) = 100*180/294=
61 per-cent.
Now go to it for the others.
2007-02-28 08:51:25 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
Aluminum Bromide Hexahydrate
2016-11-10 11:55:36 · answer #3 · answered by ? 4 · 0⤊ 0⤋
Like before, the equation you need is:
n x 18 x 100/total Mr
n is the number of water molecules
18 is the Mr of water and
total Mr includes all the water.
2007-02-28 08:49:14 · answer #4 · answered by Gervald F 7 · 0⤊ 0⤋