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L = 20x - 4x^2 - 3/2pix^2

The 3/2pix^2 is all one term.

And the pi is the symbol for pi (that's what it is in the question.)

Thanks!

2007-02-28 05:15:52 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

This one is a very simple series of power laws.

L'(x)=d/dx[20*x]-d/dx[4*x^2]-d/dx[3/2*pi*x^2]
L'(x)=20-8*x-3*pi*x
L'(x)=20-(8+3*pi)*x

2007-02-28 05:26:00 · answer #1 · answered by Tim 4 · 0 0

Derivative of L = 20 - 8x - 3 pi x

The derivative of 3/2pix^2 is simply 2x(3/2)pi the factor 3/2pi is a constant

2007-02-28 13:27:33 · answer #2 · answered by physicist 4 · 0 0

It is important to use brackets to make clear what is numerator and what is denominator.

Assume the following is intended:-
L(x) = 20x - 4x² - (3π/2).x²
L `(x) = 20 - 8x - 3π.x²

2007-02-28 13:32:15 · answer #3 · answered by Como 7 · 0 0

dL/dx=20-8x-3*pi*x

2007-02-28 13:23:16 · answer #4 · answered by santmann2002 7 · 1 0

20 -8x -3pix

2007-02-28 13:33:05 · answer #5 · answered by Adam B 1 · 0 0

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