An electron with charge q=-1.6x10-19C and mass 9.11x10-31kg moving at speed v enters into a region where the uniform magnetic field B=3.4x10-4 bends the pathy of the electron in to a semicircle with radius .041m?
1.What is the speed as it enters the region of nonzero magnetic field? ( I know sin of angle =1, and F=ma, and F=qvB to then solve for v....but i don't know what "a" is in F=ma)
2.What is the speed as it leaves the region of nonzero magnetic field? (I think this is the same as #1 b/c magnetic field can only change the direction, not the speed)
THANKS SO MUCH IN ADVANCE!
2007-02-28 04:55:47 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The angular velocity of a charge moving in a magnetic field is
w = q B / m from this you can calculate the velocity knowing r.
Note: to obtain the equation for w set the centripetal force = qvB
2007-02-28 09:35:43 · answer #1 · answered by meg 7 · 0⤊ 0⤋