An Air Bubble released from a diver's breathing apparatus at a depth of 40 m has a diameter of 2.0. When it reaches the surface of the water it has a diameter of 3.4 cm.
Show that the volume of the air bubble has increased by a factor of Approx 5.
This is NOT! My homework!
2007-02-28 04:52:30 · 4 answers · asked by Miss LaStrange 5 in Science & Mathematics ➔ Physics
Volume of a sphere is 4/3*pi*radius cubed.
So initial volume is 4/3*pi*1 cubed
do the math:
Vi = 4/3*pi cm cubed
Vi = 4.187cm cubed
Final volume Vf = 4/3*pi* 1.7 cubed
Vf = 4/3*pi*4.913
vf = 20.57
20.57 divided by 5 is 4.11.
So it works out.
2007-02-28 05:04:13 · answer #1 · answered by anon 5 · 0⤊ 1⤋
Simple volume question.
Volume of a sphere is 3/4*(pi)*(radius cubed)
The radius is half of the diameter.
solve for a diameter of 2, you get= 2.355 cm cubed
Solve for diameter of 3.4, you get= 11.5701 cm cubed
2.355/11.5701 = 4.913
2007-02-28 13:12:16 · answer #2 · answered by MSDC 4 · 1⤊ 1⤋
Just qork out the volumes at dia = 2.0 cm and at dia= 3,4 cm and compare
V1= 4/3 pi R1^3 = 4/3 x 3.14 x (2.0/2)^3 = 4.12 cu cm
V2 = 4/3 pi R2^3 = 4/3 x 3.14 x (3,4/2)^3 =20.58 cu co
Thus V2/V1 = 20.58/4.12 = 5 approx
2007-02-28 13:07:50 · answer #3 · answered by physicist 4 · 0⤊ 1⤋
volume of a sphere = (4/3) * pi * radius^3
pi = 3.14
radius = diameter / 2
you figure out the rest
2007-02-28 13:01:19 · answer #4 · answered by conventional 4 · 0⤊ 1⤋