(3x-4)(3x-5)
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
2007-02-28 03:22:02 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
first outer inner last = foil
3x x 3x=9x^2
3x x -5= -15x
-4 x 3x= -12x
-4 x -5= 20
9x^2-15x-12x+20
9x^2-27x+20
2007-02-28 03:27:38 · answer #1 · answered by SoySrtaBonita 3 · 0⤊ 0⤋
First Outside Inside Last
9x^2 -15x -12x +20
9x^2 -27x +20
2007-02-28 11:26:58 · answer #2 · answered by Sammyjo007 3 · 0⤊ 0⤋
ok, well what you do is multiply 3x and 3x together which is 9x^2
then multiply 3x and -5 which is -15x
then -4 times 3x which is -12x
and then -4 times -5 = 20
so you add them all up, so it looks like this ..
9x^2 - 15x - 12x + 20
that would be ..
9x^2 - 27x + 20
2007-02-28 11:28:38 · answer #3 · answered by x0x0sara0x0x 3 · 0⤊ 0⤋
First
Outside
Inside
Last
FOIL
F = 3x * 3x = 6x^2 (Six x squared)
O = 3x * (-5) = -15x
I = (-4) * 3x = -12x
L = (-4) * (-5) = 20
Answer: 6x^2 - 27x + 20
2007-02-28 11:31:34 · answer #4 · answered by dahighii 2 · 0⤊ 0⤋
= 9x² - 15x - 12x + 20
= 9x² - 27x + 20
2007-02-28 11:26:20 · answer #5 · answered by Como 7 · 0⤊ 0⤋
9x^2-27x+20
2007-02-28 11:25:52 · answer #6 · answered by ignoramus 7 · 0⤊ 0⤋