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(2x^6y^4z^0/3^-2x^-2y^-8z^5)^3

Cant figure this one out!!!

2007-02-28 03:18:28 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

[(2*9){x^(6+2)y^(4+8)z^(0-5)}]^3
=[18x^8y^12z^-5]^3
=5832x^24y^36z^-15

2007-02-28 03:26:25 · answer #1 · answered by Maths Rocks 4 · 0 0

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