The problem in this case is dependant upon what kind of voltages/currents we're talking about using here.
The more energy, the less resistive a material is going to be. Also, the more energy you will create in the process.
You could use salt water...beware that the water will continue to evaporate. Various metals have varying degree's of resistance...a very very long copper wire (such as 100' of low voltage wire used for speakers or something to that effect), if youre using low voltage. In fact, for a low voltage (say 12 volts) experiment, using long lengths of copper wire would be relatively safe and provide substantial resistance.
2007-02-28 03:18:42
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answer #1
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answered by Rob P 2
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well you need to have two sets of light bulbs, one is 110v and one is 220v
if you want your light to be dimmed and you have a 110 V power, then use the 220 V light bulb, you will let only 1/2 the current go threw and the light will be dimmed 1/2 way. the light bulb has to have the same Watts rating. so basically change the light bulb by using different volt rating, or by using different Watt rating.
SOMETIMES its hard in the USA to find the different rating of volts, SO YOUR ONLY CHOICE REALLY is to get different watts
so make your choices as follow
1- bright light 100 watt light bulb
2-dimmed to 1/2 use 50 watt light bulb
3-dimmed to 1/4th use 25 watt light bulb
2007-02-28 11:26:07
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answer #2
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answered by G D 1
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A simple way would be to cover the bulb with a shade of some type reducing the light coming off the bulb making sure it is not flammable or there is eoungh space between the shade and the bulb not to cause a fire.
2007-02-28 11:41:04
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answer #3
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answered by evilchass2004 2
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Resistors are almost never used to dim bulbs in real life. It would be wasteful and generate a lot of heat. Thyristors are used.
2007-02-28 11:15:04
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answer #4
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answered by Anonymous
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Use a Thyristor (or SCR) in a phase control circuit.
If you don't know what that is, go back to the books and study until you do.
HTH âº
Doug
2007-02-28 11:27:23
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answer #5
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answered by doug_donaghue 7
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Reduce the voltage
2007-02-28 11:11:18
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answer #6
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answered by physicist 4
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a series oil AC capacitor.Calculate Xc to determin the resistance.
2007-02-28 11:15:21
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answer #7
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answered by JOHNNIE B 7
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Use a battery with less voltage
2007-02-28 13:05:04
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answer #8
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answered by Anonymous
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