solve & write....?

Question

Solve and write in interval notation: -3x > 2 OR (2x + 2) / 3 > 0
(-2/3, 1)
(-1, -2/3)
(-∞, -2/3)
(-∞, ∞)


10: Solve and write in interval notation: -3 ≤ (x – 4) / 2 < 4
(-∞, ∞)
[-2, 12)
[1, 8)
(-2, Inf)


11: Solve and write in interval notation: -7 < 4x – 3 ≤ 7
(-1, 5/2]
(-1, 1]
(-∞, ∞)
(-1, ∞)


12: Solve and write in interval notation: -4x – 2 < 6 AND 3x ≥ -6
[-2, ∞)
(-∞, ∞)
(-2, ∞)
(-∞, -2]

Answer 1

9)
-3x > 2
3x < -2
x < -2/3
or
(2x +2)/3 > 0
2x+2 > 0
x > -1
Since it is OR,
Answer (-∞, ∞)

10)
-3 <= (x-4)/2 < 4
-6 <= x-4 < 8
-2 <= x <12
Answer [-2,12)

11)
-7 < 4x-3 <= 7
-4 < 4x <= 10
-1 < x <= 5/2
Answer (-1, 5/2]

12)
-4x-2 < 6
-4x < 8
4x > -8
x > -2
AND
3x >= -6
x >= -2
Answer (-2, ∞)