Help with Chemistry?

Question

Could anyone help me [teach me] how to solve the questions?

1. The conversion of glucose into ethanol and carbon dioxide is given by the following equation:
C6H¹²O6 → 2C²H5OH + 2CO²
If 24 grams of ethanol is recovered from the conversion of 50 grams of glucose, what is the % yield?

2. Refer to the Equation below:
Mg + 2AgNO³ → Mg(NO³)² + 2Ag
If 15 grams of MG and 150 grams AgNO³ are allowed to react, find: a) Limiting Reactant
B) Excess Reactant
C) ms of the ER that will be consumed in the Reaction?
D) ms of the ER that will remain unreacted.
E) The ms of CO² that will form
F) ms of H²O that will be produced.

I found it in my book but i don't understand it. ">.>

If this is hard to read you can read it here:

http://z10.invisionfree.com/ORLYNINJAS/index.php?showtopic=78

Answer 1

You have 1 mole of glucose going to 2 moles of ethanol.
1mole of glucose =

12x6 + 12 + 16x6 = 108g
50g = 50/108 = 0.463 mol

So you SHOULD end up with 0.926mol of ethanol, assuming 100% yield.

1 mol of ethanol = 2X12 + 5 + 16 +1 = 46g
24g = 24/46 = 0.523mol

predicted = 0.926mol
actual = 0.523mol
% yield = (actual/predicted)x100 = 56.48%

2)
calculate the molar masses of the reactants.
work out from the masses given how many moles are present.
the equation requires a 1:2 ratio, so it will be clear from the moles present which one is in excess.
For the masses...
You know the limiting reactant and so all the moles of that will be used. In the excess, the corresponding number will go (according to the 1:2 ratio) so you know how many moles have reacted and how many are left. You already know the molar mass, so you can work out the actual mass.

Answer 2

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Answer 3

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