1. sqroot(108) - sqroot(12)
please do not SOLVE thsi. only simplify it. if i needed to solve it i would check my calculator
2007-02-27 22:26:11 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
√108 - √12 =
√9√12 - √4√3 =
3√4√3 - 2√3 =
3 x 2 √3 - 2√3 =
6 √3 - 2√3 =
4√3
- - - - -s-
2007-02-27 23:38:00 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
â108 - â12 = â(12 x 9) - â12 = 3â12 - â12 = 2â12
= 2â(4 x 3) = 4â3
2007-02-28 06:59:27 · answer #2 · answered by Como 7 · 0⤊ 0⤋
sqrt of 108 - sqrt of 12=
6 sqrt of 3 - 2 sqrt of 3= 4 sqrt of 3
2007-02-28 09:54:46 · answer #3 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
108 = 2^2*3^3 => sqrt(108) = 2*3*sqrt(3) = 6*sqrt(3)
12 = 2^2*3 => sqrt(12) = 2*sqrt(3)
sqrt(108) - sqrt(12) = 6*sqrt(3) - 2*sqrt(3) = 4*sqrt(3)
Similar roots and normal form of roots!
2007-02-28 06:31:22 · answer #4 · answered by Bushido The WaY of DA WaRRiOr 2 · 0⤊ 0⤋
5! Simplify
2007-02-28 06:48:37 · answer #5 · answered by saints_fan412 1 · 0⤊ 0⤋
sqrt(9*12)-sqrt(12) = 3sqrt(12) - sqrt(12)= 2 sqrt(12)
2007-02-28 06:31:25 · answer #6 · answered by Anonymous · 0⤊ 0⤋
FWIW, I get
2(â27 - â3)
HTH âº
Doug
2007-02-28 06:31:57 · answer #7 · answered by doug_donaghue 7 · 1⤊ 0⤋