maths question?

Question

hi,
can someone please help me with the answer to this question?
and also show me how to solve it..
Find all the possible values for the integer n so that 9/n+1 is also an integer.
i dont understand it really.
thanks

Answer 1

There conditions that must be satisfied first...

| n+1 |<9 (the absolute value must be less than 9)

n+1 must not be equal to 0 ( hence it will be undefined)

Therefore, by deductive reasoning, the only possible values of n+1
are 1 2 3 4 5 6 7 and 8

9 = 3*3
9= 1*9

Therefore n+1 = 1, 3, or 9

Solving for the values,

n=0
n=2
n=8

considering their negatives the possible values of n are

n+1= -1, -3, -9

n=-2
n=-4
n=-10

Therefore the possible answers are

n=-10, -4, -2, 0, 2, 8

Answer 2

the first thing to do is to equate 9/n+1 to 0 so it'll be 9/n+1=0. Later remove the denominator by dividing both sides by n therefore giving you 9+n=0. Afterwords make n the subject by taking it to the right side of the equation giving you 9= -n. Then finalise by dividing both sides by -1 giving you n= -9.

Answer 3

n = {-10,-4,-2,0,2,8}

n+1
0+1=1 => 9/1=9
2+1=3 => 9/3=3
8+1=9 => 9/9=1

This is for positive values.

n+1
-2+1=-1 =>9/-1=-9
-4+1=-3 =>9/-3=-3
-10+1=-9 =>9/-9=-1

This is for negative values.

Answer 4

n+1 are factors of 9.

9's factors are 1, 3 and 9.
n is 0, 2 and 8. (1-1, 3-1, 9-1).

Answer 5

-9, -3, -1, 1, 3, 9. i.e all factors of 9 and the negative of those values.

Answer 6

so now you want us to do your homework? no wonder what is wrong with this country!!!!