Find equation of the line that contains the given pair of point and having the given slope?
(4,8), m= 13/8
The equation is y=____x+__________.
2007-02-27 20:42:43 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
y=mx+b
known slope m=13/8
need to find intercept (b)
substitute values of x and y into the equation
8=(13/8)(4) +b
8-13/2=b
16/2-13/2=b = 3/2
y=13/8x+3/2
2007-02-27 20:48:00 · answer #1 · answered by Michael 2 · 0⤊ 0⤋
y - b = m (x - a)
y - 8 = (13/8).(x - 4)
2007-02-27 20:48:21 · answer #2 · answered by Como 7 · 0⤊ 0⤋
y = (13/8)(x - 4) + 8
y = (13/8)x - 13/2 + 8
y = (13/8)x + 3/2
2007-02-27 20:49:00 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋
formulation for slope is m = (Y2 - Y1) / (X2 -X1) Given factors (-7, -2) = (X1,Y1) (-4,-3) =(X2 , Y2) m = -a million/3 and the equation is y = mx + c taking factors (-4 , -3) -3 = (-a million/3) (- 4) +c c= -13/3 y=mx +c putting m and c we get equation for the line y=(-a million/3)x -13/3
2016-11-26 20:06:30 · answer #4 · answered by campbel 4 · 0⤊ 0⤋
y-8=13/8 (x-4)
8(y-8)= 13(x-4)
8y-64= 13x-52
8y=13x-52+64
8y=13x+12
Therefore, y= 13x/8 + 1.5
or y= 13x/8 +3/2
2007-02-27 21:03:07 · answer #5 · answered by Anonymous · 0⤊ 0⤋
y-8=13/8(x-4)
y-8=13/8x-13/2
y-3/2=13/8x
13/8x-y+3/2=0
13x-8y=-12
2007-02-27 20:53:56 · answer #6 · answered by geloi 2 · 0⤊ 0⤋