the average of two consecutive numbers is 97.Find the 2 Numbers.(use variables like x) with solution and equation...who ever answers first and correct gets 5 stars!
2007-02-27 20:23:51 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
waterlily750, I know the answer...Im not letting you do my H.W.....nobody even got the correct answer now!!!so stop insulting other kids that are asking HW beacause your reach and some of us are not so GET A LIFE!!!!
2007-02-27 20:43:40 · update #1
sorry for wrong spelling...I just got very frustrated....
Excuse me...
2007-02-27 20:51:15 · update #2
oh sorry my question is wrong...IT should be 2 consecutive even numbers...Sorry!
2007-02-27 21:02:59 · update #3
why do ppl like u expect others to do their homework for them? get a life! if u dont understand something, talk to your teacher about it, and get a tutor. dont sit on yahoo and ask complete strangers to do your HW for you. odds are, ur gonna get a wrong answer anyways.
2007-02-27 20:28:36 · answer #1 · answered by waterlily750 4 · 0⤊ 2⤋
Ok... using the average=mean if the two numbers are x and y. Then set y = x+1 (since the two are consecutive)
and (x+y)/2 = 97
(x+x+1)/2=97
x+0.5 = 97
x =96.5 ; y = 97.5
which doesn't make sense, as x and y are whole numbers
So... we are reduced to either the median orthe mode of two consecutive numbers being 97.
The median is the middle value. In the case of there being an even number of numbers the median is normally taken to be the mean of the two middle numbers... and we are in teh same situation as before.
Mode. This is the most common value(s). So this leaves us with two options {96,97} or {97,98} In the first case the modes are 96 and 97, and in the second the modes are 97 and 98.
*EDIT* Two consecutive even numbers...
Then y = x+2
(x+y)/2 = 97
(x+x+2)/2 = 97
x+1 = 97
x=96 ; y = x+2 = 98
2007-02-27 20:52:57 · answer #2 · answered by robcraine 4 · 0⤊ 0⤋
I see nothing wrong with asking your question here. Sometimes teachers aren't helpful and not everyone can afford a tutor.
Let x be the first of the two numbers. The next consecutive number is x+1.
The average of any two numbers A and B is (A+B)/2, apply this to your unknown numbers: Average = [x + (x+1)]/2. This is 97, so
[x + (x+1)]/2 = 97;
2x + 1 = 2*97; solve for x and calculate x+1.
2007-02-27 20:33:36 · answer #3 · answered by gp4rts 7 · 0⤊ 0⤋
Let x = The first number
Let (x + 1) = the second number
[x+(x+1)]/2 = 97
x +(x+1) = 194
2x +1 = 194
2x = 193
x = 96.5
so.. x+1 = 97.5
So, the two consecutive numbers are 96.5 and 97.5.
2007-02-27 20:32:47 · answer #4 · answered by Anonymous · 0⤊ 0⤋
97 is the average of 96 and 98, which are two consecutive even numbers.
2007-02-27 21:05:48 · answer #5 · answered by Helmut 7 · 0⤊ 0⤋
Let x be the first number and x+1 the second number, since they are consecutive.
x + ( x+1 ) / 2 = 97
2x+1= 194
2x=193
x= 46.5
x + 1= 47.5
2007-02-27 20:50:15 · answer #6 · answered by Anonymous · 0⤊ 1⤋
96 and 98
96+98=194
194/2=97
97 +1=98
97-1=96
2007-03-03 18:10:43 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Let numbers be x and x + 1
(x + x + 1) / 2 = 97
2x + 1 = 194
2x = 193
x = 96.5 and x + 1 = 97.5
The numbers are 96.5 and 97.5
2007-02-27 20:38:39 · answer #8 · answered by Como 7 · 0⤊ 0⤋
let the numbers br x and x+1.
(x + x + 1)/2 = 97
2x + 1 = 194
x = 96.5
two numbers are 96.5 and 97.5
2007-02-27 20:29:45 · answer #9 · answered by rohan g 1 · 2⤊ 0⤋
( x + x+2)/2 = 97
2x+2=194
2x=192
x=96
the nos. are 96 & 98...
2007-02-27 20:59:39 · answer #10 · answered by Neby 2 · 0⤊ 1⤋