what equation do i use to find distance when using horizontal/vertical motion?

Question

when im trying to find the "distance" im not sure wheather i should be using "speed=distance/time" or the other "d=vi t + 1/2 at2?

Answer 1

If there is acceleration, that is to say, the moving object is speeding up or down, rather than traveling at a stable velocity, then you need to use the second formula.

If the object is moving at a constant speed then use the first formula.

So, for the horizontal motion, use the first for the vertical motion use the second.
the acceleration is g, for the vertical vector of the speed which is about 9.8 m/s^2
Cheers

Answer 2

The ball will take 27.4 / 40 5 = 0.609 s to realize first base. throughout that component it fairly is going to drop. Drop = 0.5 . g . t^2 = a million.80 two m The final equation comes right now from d = u.t + (a .t^2 / 2 ) the place the preliminary downward velocity ( u ) is 0. This ball would be at approximately floor point however the glove could %. it up.

Answer 3

S = ut + 1/2 a t^2

where S is the distance
u the initial velocity
a the acceleration
t the time

v = u + at (v is the final velocity) is also handy.

v = d/t is a definition of velocity.

Answer 4

Elaborate please; Speed=Distance/Time has almost nothing to do with horizontal/vertical motion.
If you are doing projectile motion (or any horizontal/vertical motion), use d=di+vi*t+1/2at^2
A clarification on your question would be nice.