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explain, please.

3x^5 - 6x^3 + 3x =

i'm supposed to factor completely, if possible. thanks

2007-02-27 16:45:50 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

First, factor out an x
x*(3x^4 - 6x^2 + 3) Now replace x^2 with u so that
3x^4 - 6x^2 + 3 becomes
3u² - 6u + 3 which factors as
(3u - 3)*(u - 1) Now replace the u with x^2 and get
x*(3x^2 - 3)*(x^2 -1) which will further factor into
x*(3*(x + 1)*(x - 1))*(x + 1)*(x - 1) or
3*x*((x + 1)^2)*((x - 1)^2)

HTH ☺


Doug

2007-02-27 16:56:58 · answer #1 · answered by doug_donaghue 7 · 0 0

Take out all the x's and 3's so.. 3x(x^4-2x^2+1) i am to lazy to do the rest so i suggest you do yor own work cause I have to finish being lazy.

2007-02-28 00:50:53 · answer #2 · answered by Shawn J 3 · 1 1

3x^5 - 6x^3 + 3x =3x*(x-1)*(x-1)*(x+1)*(x+1) >>or>> 3x*(x-1)^2*(x+1)^2

2007-02-28 00:55:01 · answer #3 · answered by XC RUNNER 2 · 0 0

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