Sodium nitrate, potassium chloride, barium sulfate
2007-02-27 16:06:02 · 4 answers · asked by blue_eyed_dancer13 1 in Science & Mathematics ➔ Chemistry
Sodium nitrate
NaOH (aq) + HNO3 (aq) --> NaNO3 (aq) + H2O (l)
Potassium chloride
KOH (aq) + HCl (aq) --> KCl (aq) + H2O (l)
Barium sulfate
Ba(OH)2 (aq) + H2SO4 (aq) --> BaSO4 (aq) + 2 H2O (l)
2007-02-27 16:15:34 · answer #1 · answered by Richard 7 · 9⤊ 0⤋
sodium nitrate - NaNO3 is produced from the strong acid nitric acid - HNO3 & the strong base sodium hydroxide NaOH
HNO3 + NaOH ---> NaNO3 + H2O
potassium chloride - KCl is produced from the strong acid hydrochloric acid - HCl & the strong base potassium hydroxide KOH
HCl + KOH ----> KCl + H2O
barium sulfate - BaSO4 is produced from the strong diprotic acid sulfuric acid - H2SO4 & the strong base barium hydroxide BaOH
H2SO4 + BaOH ----> BaSO4 + H2O
all reactions of strong acids and/or strong bases react 100%, that is the ions dissociate completely in solution. water is always a byproduct of a reaction between a strong acid and strong base.
2007-02-28 00:16:45 · answer #2 · answered by Jon from u of florida 2 · 0⤊ 0⤋
These are balanced equations; not simplified to net ionic equations.
HNO3 + NaOH -> H2O + NaNO3
HCL + KOH -> H2O + KCL
H2SO4 + Ba(OH)2 -> 2H2O + BaSO4
2007-02-28 00:13:51 · answer #3 · answered by nothereanymoreomgteh 4 · 0⤊ 0⤋
NaOH + HNO3 -> NaNO3 +H20
KOH +HCl->KCl +H20
Ba(OH)2+ H2SO4 -> BaSO4 + 2H2O
2007-02-28 00:15:42 · answer #4 · answered by apspublic 2 · 0⤊ 0⤋