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A ground state H-atom absorbs a photon of wavelength 93.78 nm and its electron attains a higher energy level. The atom then emits two photons: one of wavelength 2625.9 nm to reach an intermediate level and a second to return to the ground state. What was the wavelength of the second photon emitted?

2007-02-27 15:12:21 · 1 answers · asked by socr8711 2 in Science & Mathematics Chemistry

1 answers

Energy is conserved. The total energy emitted will be equal to the energy absorbed. The energy of a wave is given by the equation:

E = hc / (lambda)

where h is Planck's constant, c is the speed of light, and lambda is the wavelength of the wave. You don't even need to use h or c since they will cancel at. Just set up the equation:

E(absorbed) = E(emitted) = E(photon1) + E(photon2)

2007-02-27 15:44:05 · answer #1 · answered by trickshottim.com 6 · 0 0

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