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If .00625 mols of HCl are mixed with .00255 mols of Ba(OH)2, what is the pH of the resulting solution?

2007-02-27 14:30:34 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

pH =

-log [(mol HCl - mol Ba(OH)2) / (volume HCl + volume Ba(OH)v2)]


Just substitute the values. Problem is, you do not have the volumes of both species.

Hope this helped.

2007-02-27 14:47:39 · answer #1 · answered by lmmonisit 2 · 0 1

What volume? What is your concentration here?

2007-02-27 14:39:41 · answer #2 · answered by bloggerdude2005 5 · 0 0

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