please help!!!!!!!!!!!!?

Question

Its solving equations with variables on both sides. please explain

2(4-a)=3(a+1) - 5(a-1)

Answer 1

you first have to multiply 2,3,and -5 to the things in the parentheses. then you have to add or subtract numbers or varables to get the variable on one side, then solve.

Answer 2

This was close, except for one error.

Get rid of all those parentheses first:

2(4-a) becomes 8 - 2a
3(a +1) becomes 3a +3
5(a-1) becomes 5a - 5

So your whole equation is:

8 - 2a = 3a + 3 - 5a

Watch out here, though, because that negative sign gets used for both the 5a and the - 5, so it turns into a plus
8 - 2a = 3a + 3 - 5a - (-)5
Then combine like terms:

8 - 2a = 8a +8

Get all of the a's on one side, and the non-a's on the other:

8 = 10a + 10
-10+8=-2 = 10a
-2 = 10a

and then divide by 10 to get a alone

a = -2/10, or -1/5

Answer 3

It might look complicated, but all you need to do is simplify. Get rid of all those parentheses first:

2(4-a) becomes 8 - 2a
3(a +1) becomes 3a +1
5(a-1) becomes 5a - 5

So your whole equation is:

8 - 2a = 3a + 1 - 5a - (-)5

Watch out here, though, because that negative sign gets used for both the 5a and the - 5, so it turns into a plus

Then combine like terms:

8 - 2a = 8a +6

Get all of the a's on one side, and the non-a's on the other:

8 = 10a + 6
2 = 10a

and then divide by 10 to get a alone

a = 2/10, or 1/5

Answer 4

Guy above did it wrong

8-2a=3a+3-5a+5
8-2a=-2a+8
subtract and add to both sides -2a and 8 respectively
0=0 which is always true, therefore any value for a will be true

to check pick a random number :a=3
2(4-3)=3(3+1) - 5(3-1)
2=12-10
2=2

Answer 5

Hey, it's too easy. If I can I will explain you but I don't think so because my english is not very well but i will try to do my best,
just keep looking.

ok, first multiple 2 and 4, (2x4)=>8 , then 2xa=> 2a, then put the = the multiple 3 and a, (3xa)=>3a, then 3x1=> 3 then put the - then multiple 5xa=>5a then 5x1=>5
then result of all of these is: 8-2a=3a+3-5a+5
then you should do the right side of =, it mean's letter by letter's and number's by number's, it means: 3a-5a=> -2a and 3+5=8

I hope to explane it good for you and you'll undrestand it.

Answer 6

First you want to get all of the variables on one side.

(8-2a)=(3a+3)-(5a-5)
8-2a = 3a+3-5a+5
8-5-3=2a+3a-5a
0 = 0

Answer 7

8 -2a = 3a+3 -[5a-5]
8 - 2a = 3a + 3 -5a+5
-2a-3a+5a = 3+ 5- 8
0= 0

Answer 8

8-2a = 3a + 3 -5a + 1 (removing brackets)

8-2a = -2a + 4
hence
a=0
Sub a=0 the eq is satisfied.

Answer 9

2*4-a=3a+1-5a-1

8-a=8a
3a+1=
4a-4a=a
8a=a then what does a=??

Answer 10

cormelius has the correct answer, all the others are wrong in either the distributive property or in adding/subtracting.