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Calculate the molality, new boiling point, and new freezing point of a solution that is prepared by adding 25 grams of glucose (GMM = 180) to 100mL of water.

2007-02-27 11:55:34 · 1 answers · asked by diab01ical 2 in Education & Reference Homework Help

1 answers

Molality is moles of solute / kg of solvent. For water, it's important to remember that 1 mL of water weighs 1g.

Moles of solute = 25 g / 180 g/mol = .1389 moles
kg of solvent: 100 mL = 100 g = .1 kg

Molality = moles / kg of solvent = .1389 moles / .1 kg = 1.389 molal (solution!)

2007-02-28 00:55:52 · answer #1 · answered by ³√carthagebrujah 6 · 0 0

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