At t=0 a car has a speed of m/s. At t=6s, its speed is 14m/s. What is its average acceleration?

Question

I dont know how to find the average acceleration during this time interval. Will someone help me?

Answer 1

You haven't actually specified what the initial speed of the car is, without that no one can tell you anything.

In general though:

average acceleration = (final speed - initial speed)/time

which in your case would be:

(6 - initial speed)/6

so just plug your initial speed value into that and you're sorted.

Answer 2

If the car is at rest (0 m/s) and 6 seconds later is at 14 m/s, the average acceleration is 14/6 m/s^2 or 2 and 1/3 m/s^2.

Answer 3

I think you forgot to write the speed at t=0 (I am assuming that it is 0 m/s).

However, no matter what value it is, you can use the equation:
Average acceleration=(change in velocity)/(change in time)=(v2-v1)/(t2-t1)

In this case,
(14 m/s - 0 m/s)/(6 s - 0 s)= (14 m/s)/(6 s)=2.33 m/s^2

Answer 4

Average Acceleration = (Final velocity - Starting Velocity) / (Change in time)

If it started from rest, it's (14 m/s - 0 m/s) / (6s - 0s) = 2.33 m/s/s

Answer 5

v = u + at

v= Final Velocity
u = Initial Velocity (assuming it is zero you meant?)
a = Accelleration
t = Time in seconds

v = u + at
14 = 0 + a.6
a.6=14 - 0
a = 14 /6
= 2.333 m/s^2

I hope this helps?!

Answer 6

You left out the initial speed.

But basically, the average velocity is Delta V / Delta t: (Change in velocity over change in time)

V1 = ???

V2 = 14m/s

t1 = 0

t2 = 6

Just plug that information into the equation:

(V2 - V1) / (t2-t1)

And you should get the average velocity. :)