density of seawater is 1025kg/cu.m. and g= 9.8 N/kg find the ff?
a. buoyant force of sea water in stone
b. volume of dispaced water
c. volume of the stone
2007-02-27 08:42:54 · 4 answers · asked by eden 2 in Science & Mathematics ➔ Physics
a) The weight of water displaced is the buoyant force, which is given by 200N - 140N = 60N
b) 60N / 9.8N/kg = 6.12 kg is the mass of water displaced
6.12 kg / 1025 kg/ cu.m. = 0.0060 cu.m.
c) doh, it's the same as the water! took me a while
2007-02-27 09:48:21 · answer #1 · answered by slipknotraver 4 · 0⤊ 0⤋
a) The bouyant force of the seawater = 200 N-140 N = 60 N
b) We first need to find the mass of the displaced seawater. The weight of the displaced seawater will be 60 N so we have:
mg=m9.8=60
Mass of the displaced seawater is 60/9.8 = 6.12 kg
Then we can calculate the volume using the density.
Volume v = mass/density = 6.12/1025 = 0.0060 meters^3
c) volume of the stone must be the same as the volume of displaced seawater so its (again) 0.0060 meters^3
2007-02-27 09:50:13 · answer #2 · answered by heartsensei 4 · 0⤊ 0⤋
a. 60 N = 200 - 140
b. = c. = 60/(9.8*1025) = .00597 m³
2007-02-27 09:53:00 · answer #3 · answered by Steve 7 · 0⤊ 0⤋
c.
2007-02-27 10:01:30 · answer #4 · answered by Anonymous · 0⤊ 0⤋