x-2y=8 -x+3y=-5?

Answer 1

You can also solve by substituting the quation
Using the 2nd equation to solve for x, x=3y+5
Then plug into the first equation for x
(3y + 5) - 2y = 8 gives >>> y+5=8 so y=3
then solve with either equation with y=3.

Answer 2

Okay, this problem can be solved by using linear combinations

First, you line up your two linear systems like so:

x - 2y = 8
-x + 3y = -5

Now you just solve the systems like how you would when you add or subtract numbers:

x - x = 0 or nothing
-2y + 3y = 1y or y
8 - 5 = 3

So, all you have left now is y = 3

Now, plug the value of y back into atleast one of the systems to solve for x:

*Just to help you, I will show you both systems*

x - 2y = 8
x - 2(3) = 8
x - 6 = 8
Add 6 to both sides
x = 14

-x + 3y = -5
-x + 3(3) = -5
-x + 9 = -5
Subtract 9 from both sides
-x = -14
-x / -1 = -14 / -1
x = 14

If you have done the systems correctly, both systems should have the same value for each variable.

Finally, the answer to the problem is:

x = 14
y = 3

or...

(14,3)

Answer 3

Okay, you've already got your equations set up to get rid of the X, because you can only solve for one variable at a time. So set up your equations like this:

x - 2y = 8
-x + 3y = 5

And then add them together, noting that the x's cancel out. So you're left with just y = 3.

Then plug y=3 into the first equation:

x - (2)(3) = 8

x - 6 = 8

x = 14

And then check by plugging it all back into the second equation

Answer 4

x-2y=8
ignore the x.
2y=8
y=4
x-8=8
x=16

Answer 5

x-2y=8 -x+3y=-5
y=1/2x-4 y=1/3-5/3
1/2x-4=1/3x-5/3
1/6x-4=-5/3
1/6x=2 1/3
x=14

y=1/2x -4
y=1/2(14)-4
y=7-4
y=3


x=14 y=3

Answer 6

y=13, x=34

Answer 7

is this not two separate equations?
if so solve for x and then substitute the value for x and solve for y

x = 14
y = 3

Answer 8

its 42

Answer 9

use the method of elimination

Answer 10

what are we solving for? x and y?