Next three terms in each sequence?

Question

Can someone tell me the next three terms in each sequence? It's Algebra 1 homework. lol :]


1. 0,1,8,27
2. a + 1, a + 4, a + 9
3. 1,4,10,19,31
4. y, 4y, 9y, 16y

Answer 1

1. 0,1,8,27,64,125,216 (exponential power of 3)
2. a+1, a+4, a+9, a+16, a+25, a+36 (exponential power of 2)
3. 1,4,10,19,31,46,64,85 (x+multiples of 3)
4. y, 4y, 9y, 16y, 25y, 36y, 49y (exponential power of 2)

Answer 2

The mathematics sequence equation is: an = a1 + (n – a million)d we commit to locate the values for a1 and d, then sparkling up for an. a1 = the first time period of the sequence d = the common distinction 3, 7, 11,... a1 = 3 d = 7 - 3 = 4 = 11 - 7 = 4 d = 4 next step you'll plug interior the solutions into the equation then sparkling up for an. an = 3 + (n - a million)4 an = 3 + 4n - 4 an = 4n - a million for each sequence to double verify you've the right equation plug a million into your equation to locate the first time period, n = a million, n = 2, n = 3, etc time period a million: 4(a million) - a million = 3 time period 2: 4(2) - a million = 7 time period 3: 4(3) - a million = 11 time period 4: 4(4) - a million = 15 time period 5: 4(5) - a million = 19 time period 6: 4(6) - a million = 23 So, the subsequent 3 words of the first sequence is 15, 19, 23 b) 5.8, 7.2, 8.6 a1 = 5.8 d = 7.2 - 5.8 = a million.4 8.6 - 7.2 = a million.4; so d = a million.4 an = 5.8 + (n - a million)a million.4 = 5.8 + a million.4n - a million.4 = a million.4n + 4.4 a million.4(a million) + 4.4 = 5.8 a million.4(2) + 4.4 = 7.2 a million.4(3) + 4.4 = 8.6 a million.4(4) + 4.4 = 10 a million.4(5) + 4.4 = 11.4 a million.4(6) + 4.4 = 12.8 So, the subsequent 3 words are 10, 11.4, 12.8 for c you do the very similar element as I did for a and b. wish this helps.

Answer 3

1. 64

2. a + 16

3. 46

4. 25y