If an object is propelled upward from a height of 16 feet with an initial velocity of 48 feet per second, its height is given by the equation h = -16t² + 48t + 16, where h is in feet. After how many seconds will the object reach a height of 52 feet?
Can you please help show me how I would answer this question? Thank you!!!
2007-02-27 08:04:39 · 3 answers · asked by o_lena_angel_o 1 in Education & Reference ➔ Homework Help
It's just a quadratic equation, plug in 52 for h
so 52= -16t^2 +48t +16
Bring 52 to the other side
0 = -16t^2 + 48t - 36
Now take out -4 and factor
-4 (4t^2 - 12t + 9)
-4 (2t - 3) x (2t - 3)
Set 2t - 3 = 0, and solve for t. So t = 3/2, or 1.5 seconds.
2007-02-27 08:14:31 · answer #1 · answered by crzywriter 5 · 0⤊ 0⤋
to answer this question you would take a number (preferably between 0 and 5) and substitute (t) in the equation with the number you chose. Eventually with some modifications to (t) h will equal 52. There is another way but it is advanced algebra 2 and I do not want to confuse you.
2007-02-27 08:12:51 · answer #2 · answered by Scooter 2 · 0⤊ 0⤋
h = -16t² + 48t + 16,
52 = 32t(sqaured) + 16 (i think)
*minus 16 on both sides*
36 = 32t(sqaured)
*dived 32 by both sides*
1.13 = t(squared)
*square 1.13*
t = 1.06
*thats what i got...but im not positive its right*
2007-02-27 08:13:51 · answer #3 · answered by Rebecca N 1 · 0⤊ 0⤋