Train A and Train B math question.?

Question

Train A leaves the station at 8 am. It travels at 40 miles per hour. It's destination is 200 miles away. The train heads south to get there.

Train B leaves at 12 pm. It travels 60 miles an hour. It has the same destination, but is 250 miles away. The train heads north to get there.

Who will arrive first?

no one has the right answer yet...keep going

Answer 1

Train A
200miles/40miles per hour =5 hours

Train B
250miles/60miles per hour = 4.16hours

Train A will arrive at 8 AM plus 5 hours or 1PM
Train B will arrive at 12PM plus 4.16 hours or 4:10 PM

Train A will arrive first. 3 hours and 10 minutes ahead of train B.
Direction makes no difference

Answer 2

If train B 250 miles south of the station when it start out it will arrive at the destination at 12:50pm. Train A will arrive at 2:00pm.

Answer 3

Train A will take 5 hours and arrive at 1pm
Train B will take 4 hours and 10 minutes and arrive at 4.10pm
Train A will arrive first

Answer 4

i THINK train A
train a travels for 5 hours - arriving at 1pm
train b travel for 4 hours and 6 minutes - arriving at around 4pm

This is just a guess tho, hope it helps

Answer 5

Train A:

200/4 = 5

8AM + 5 = 1PM

Train B:

250/60 = 4.16...

12PM + 4.16... = 4.16PM

So Train A will arrive there first!

Answer 6

train a arrives in 5hr @ 1pm t=d/r 200/40

train b arrives in 4hr 10 min @ 4:10pm 250/60

t-time (hrs)
d-distance (miles)
r-rate (mph)

answer train a

Answer 7

practice A________Train B 40 mph________48 mph 5 : 25__________5 : 40 In quarter-hour practice A travels 10 miles Relative velocity of trains is 8 mph Time for practice B to return and forth 10 miles is given by skill of :- 10/8h = 5/4h = 1h 15min

Answer 8

Train A? 1pm.
B at 4:10 pm.

I guess... But I had maths long time ago.