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I dont understand how you come up with calculations to do dilutions. The problem i'm given is that the stock solution of bromothymol blue is 15 ppm. It says to set up a dilution scheme and use it to produce samples of different concentrations (0, 1, 2, 5, 10, and 15).Then i measure the absorbance with the spectrophotometer,e tc. Thank you for any help!

2007-02-27 05:34:24 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

Let's start at both ends first. Your 0 wil just be water or whatever solvent you are using (I'm going to assume water), and your 15 would just be the straight stock solution.

Basically, you can use C1V1 = C2V2 to do all of your calculations. Suppose you want to make 6 mL of each of your final solutions. For your 10 ppm solution, you would calculate V1 from:
V1=(6 mL) (10 ppm)/15 ppm
V1 = 2 mL

So, you'd take 2 mL of your 15 ppm solution and add 4 mL of water to make 6 mL of 10 ppm solution.

If you repeat this calculation changing only the final concentration (C2) each time, you'll get there.

2007-02-27 05:42:59 · answer #1 · answered by hcbiochem 7 · 0 0

Dilution Scheme

2016-11-12 07:16:20 · answer #2 · answered by ? 4 · 0 0

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RE:
How do you come up with a dilution scheme?
I dont understand how you come up with calculations to do dilutions. The problem i'm given is that the stock solution of bromothymol blue is 15 ppm. It says to set up a dilution scheme and use it to produce samples of different concentrations (0, 1, 2, 5, 10, and 15).Then i measure the...

2015-08-18 15:31:52 · answer #3 · answered by Marice 1 · 0 0

Assume, say, a total volume of 15ml. 0 is pure water, 1 is 1ml + 14ml water, 5 is 5 ml + 10 ml water and so on. 15 is undiluted.

2007-02-27 05:40:18 · answer #4 · answered by Gervald F 7 · 2 0

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