All lines with gradient - 1/3 are perpendicular to this line.
Lines will have equation as follows:-
y = - (1/3)x + C where C is a constant
2007-02-27 03:59:06
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answer #1
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answered by Como 7
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Here's the perpendicular to the equation y=3x-8:
y=-1/3x-8
2007-02-27 11:32:43
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answer #2
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answered by Anonymous
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Your line has slope 3, so any line with a slope of -1/3 is perpendicular to it.
2007-02-27 11:28:18
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answer #3
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answered by Anonymous
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y = -1/3x + C
A perpendicular line has a negative reciprocal slope. It can pretty much have any y-intercept ( + C)
2007-02-27 11:28:53
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answer #4
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answered by Bhajun Singh 4
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Rise of line is +3 (Rise of 3 per run of 1). Intercept is irrelevant.
Rise of perpendicular lines is -1/3 (Rise of -1 per run of 3). Again, intercept is irrelevant, unless defined by the problem.
2007-02-27 11:36:12
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answer #5
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answered by Jim T 6
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Any line that starts off
y = (-1/3)x plus anything
HTH âº
Doug
2007-02-27 11:30:24
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answer #6
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answered by doug_donaghue 7
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y = 1/3 x + C
Slope: 1/3
y-intercept: any number
.
2007-02-27 11:30:59
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answer #7
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answered by tlbs101 7
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-3x
2007-02-27 11:27:33
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answer #8
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answered by Anonymous
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