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y = 3x - 8?

2007-02-27 03:25:35 · 8 answers · asked by ceomillionman 1 in Science & Mathematics Mathematics

8 answers

All lines with gradient - 1/3 are perpendicular to this line.
Lines will have equation as follows:-
y = - (1/3)x + C where C is a constant

2007-02-27 03:59:06 · answer #1 · answered by Como 7 · 0 0

Here's the perpendicular to the equation y=3x-8:
y=-1/3x-8

2007-02-27 11:32:43 · answer #2 · answered by Anonymous · 0 0

Your line has slope 3, so any line with a slope of -1/3 is perpendicular to it.

2007-02-27 11:28:18 · answer #3 · answered by Anonymous · 0 0

y = -1/3x + C

A perpendicular line has a negative reciprocal slope. It can pretty much have any y-intercept ( + C)

2007-02-27 11:28:53 · answer #4 · answered by Bhajun Singh 4 · 1 0

Rise of line is +3 (Rise of 3 per run of 1). Intercept is irrelevant.

Rise of perpendicular lines is -1/3 (Rise of -1 per run of 3). Again, intercept is irrelevant, unless defined by the problem.

2007-02-27 11:36:12 · answer #5 · answered by Jim T 6 · 1 0

Any line that starts off
y = (-1/3)x plus anything

HTH ☺


Doug

2007-02-27 11:30:24 · answer #6 · answered by doug_donaghue 7 · 1 0

y = 1/3 x + C

Slope: 1/3
y-intercept: any number

.

2007-02-27 11:30:59 · answer #7 · answered by tlbs101 7 · 0 1

-3x

2007-02-27 11:27:33 · answer #8 · answered by Anonymous · 0 4

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