2x-y=4
y =2-x?
2007-02-27 03:23:53 · 8 answers · asked by ceomillionman 1 in Science & Mathematics ➔ Mathematics
Take the second equation and replace it for where the y is:
2x-(2-x)=4
2x-2+x=4
3x-2=4
3x=6
x=2
y=2-2
y=0
The solution set is (2,0)
Check:
2(2)-0=4
4=4
0=2-2
0=0
I hope this helps!
2007-02-27 03:30:41 · answer #1 · answered by Anonymous · 4⤊ 0⤋
2x-y=4
-x-y= -2 (transposing the values)
Subtracting the two equations:-
2x - y=4
-2x - 2y= -4
= y=8
Substituting the value of y=8 in equation 1..
2x - 8 = 4
2x = 4+8
2x = 12
x= 12/2
Therefore, x= 2
The solution to the given system is
x=2 , y=6
2007-02-27 03:45:57 · answer #2 · answered by suchi- i rock! 1 · 0⤊ 0⤋
2x-y=4
y =2-x
you replace y =2-x in 2x-y=4 and get:
2x-(2-x) =4 and now 2x -2+x=4 = 3x-2=4 = 3x=6, so x=2. But you know y =2-x , so y= 2-2 =0.
2007-02-27 03:45:13 · answer #3 · answered by Anonymous · 1⤊ 0⤋
Add the equations to obtain
2x= 4 + (2 -x) = 6 - x ==> x = 2
Substitution in one of the equations gives y = 0
2007-02-27 03:29:59 · answer #4 · answered by physicist 4 · 1⤊ 0⤋
2x - y = 4
x + y = 2-------ADD equations
3x = 6
x = 2
2 + y = 2
y = 0
Solution is x = 2, y = 0
2007-02-27 04:16:33 · answer #5 · answered by Como 7 · 1⤊ 0⤋
x=2
y=0
2007-02-27 03:32:09 · answer #6 · answered by Anonymous · 1⤊ 0⤋
2x-y=4
2x-(2-x)=4
2x-2+x=4
3x-2=4
3x=4+2
3x=6
x=6/3
x=2
y=2-x
y=2-2
y=0
Your solution is (2,0)
2007-02-27 03:39:33 · answer #7 · answered by ema 3 · 1⤊ 0⤋
2x-y=4
y=2-x
2x-2x-y=4-2x
y=-2x-4
-y/-1=-2x/-1-4/-1
y=2x+4
y=2-x
2007-02-27 03:41:23 · answer #8 · answered by Rudeline C 1 · 1⤊ 0⤋