A GRAMOPHONE ROTATESAT 60 RPM. A COIN OF MASS 18GM IS PLACED AT A DISTANCE OF 8CM FROM THE CENTRE. CALCULATE THE CENTRIFUGAL FORCE. ANSWER=4105.92 DYNE (PI^2)=9.87
2007-02-27 03:02:10 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
F = Rω²m = R(2πf)²m = 4π² Rf²m =
39.4784 x 8cm x 1²/s² x 18g = 5485 g cm/s² = 5485 dyn
2007-02-27 05:33:54 · answer #1 · answered by Alexander 6 · 0⤊ 0⤋
Centrifugal force = m.r.w^2
Hence, F = 18 x 8 x (2 . pi. 60 / 60)^2
F = 5684.89 dynes
2007-03-02 10:33:23 · answer #2 · answered by Bharat 4 · 0⤊ 0⤋
a=V^2/r
rotating one per second (60 RPM) the distance covered is 2pi(r),
that gives a velocity of about 50.25 cm/s
now, you might want to choose to convert your terms to meters and Kg, or whatever depending on what's asked for but once you have a, and mass was given, just plug in for F=ma
2007-02-27 11:40:34 · answer #3 · answered by SteveA8 6 · 0⤊ 0⤋