how to solve 8x-9<3x-11 and 9<=5x+3<19 can u explain how to do it please?

Answer 1

ok if its separate then
8x-9<3x-11
5x-9<-11 subtract 3x from both sides
5x<-2 add 9 on both sides, then
x< -2/5

9<=5x+3<19 first separate the two inequalities making
9<=5x+3 and 5x+3<19
6<=5x and 5x<16
6/5<=x and x<16/5 so
6/5<=x<16/5 combine the two

Answer 2

firstly , 8x-9<3x-11
move the x over to one end and the constant to the other end
for me, i chose to move 3x to the left and 9 to the right

this would result in
5x>-2
divide throughout by 5
this will give u
x> -(2/5)

then for 9<= 5x+3<19
basically, u solve for those 2 equations separately
ie. solve for 9<= 5x+3 , and 5x+3 < 19 separately and then find the intersection of the answers

for 9<= 5x +3
move 3 to the left, which will give 6<= 5x
divide thruout by 5, u will get 6/5 <= x

for 5x+3<19,
move 3 to the right
this will give u 5x< 16
divide throughout by 5, u will get x< 16/5

then the ans is the intersection of x>=6/5 and x<16/5
ie. 6/5 <=x<16/5

Answer 3

8x - 9 ≤ 3x - 11
8x - 3x ≤ -11 + 9
5x ≤ - 2
x ≤ - 2/5

9 ≤ 5x + 3
6 ≤ 5x
x ≥ 6/5

But 5x + 3 < 19
5x < 16
x < 16/5

Thus 6/5 ≤ x < 16/5

Answer 4

1)8x-9<3x-11
Subtract 3x from both sides:
5x-9<-11

Add 9 from both sides:
5x<-2

Divide 5 from both sides:
x<-2/5

2)9≤5x+3<19
Subtract 3 from both sides:
6≤5x<16

Divide 5 from both sides:
6/5≤x<16/5

I hope this helps!