Expand (A+B)^6?

Question

(A+B)^6
that is (A+B)(A+B)(A+B)(A+B)(A+B)(A+B)


How do I do it?
I am having trouble remembering how to do it, so could you please so working?

A^6 + B^6. is not the answer.

(1+2)^2 != 1+4 != 1^2+2^2
=9

Answer 1

What the two people above me have been telling you on guidance is correct, but if you want the correct answer, here it is:

a^6+6a^5b+15a^4b^2+20a^3b^3+15a^2b^4+6ab^5+b^6

Hope you got that. My pencil is burning up after that one.

Edit: You have to hang your curser over the answer because for some reason the entire answer is not showing up. Just place the arrow over the answer for a few seconds, and the answer will appear in a yellow box.

Answer 2

A^6 + 6*A^5*B + 15*A^4*B^2 + 20*A^3*B^3 + 15*A^2*B^4 + 6*A*B^5 + B^6

I did it in following manner
(A+B)^6
=(A+B)*(A+B)*(A+B)^4
=(A^2 + 2AB + B^2)*(A+B)^4
=(A^2 + 2AB + B^2)*(A+B)*(A+B)^3
...
so on

Answer 3

one at a time
(a+b)(a+b) = a^2 + 2ab + b^2
times (a+b) a^3 +2a^2b + ab^2 + a^2b + 2ab^2 + b^3 =
a^3 + 3a^2b + 3ab^2 + b^3 - that's the third one

multiply this three more times a times everything - then b x everthing and reduce the same ab combos

best of luck!