I am planning to do a lab, and it says for us to:
1) make a solution of lead nitrate (power form) and a separate solution of potassium iodide (powder form).
My question is, how do you make the solutions?
do you just mix it with water?
after, would the solutions be a clear color? or what other observations would I have? I already did this lab once, but it failed, so i have to redo it, and I would like to know what to expect.
2) then we have to mix the two solutions together
after seeing another group, it turned yellow, and a precipitate formed.
is this correct?
2007-02-26 20:06:15 · 4 answers · asked by blubbablub 1 in Science & Mathematics ➔ Chemistry
1) Probably make them with distilled water or whatever purified water you are using.
2) Yeah, Lead Nitrate is a yellow precipitate
2007-02-26 20:37:45 · answer #1 · answered by Anonymous · 0⤊ 0⤋
you get an insoluble yellow compound extensive-unfold as lead (II) iodide and a answer of saltpeter (potassium nitrate). it extremely is going to be a yellow precipitate, it extremely is insoluble in water and in maximum answer. its a undemanding element in yellow paint for this reason the toxicity of it. potassium nitrate would be in answer, it extremely is a sparkling coloration and is independent. the reaction would be exothermic. as potassium nitrate releases warmth whilst made, the reaction is spontaneous.
2016-11-26 01:37:23 · answer #2 · answered by krolick 4 · 0⤊ 0⤋
Just mix with distilled water.
What molarity or concentration do you need? then you have to mix appropriately.
The solutions would likely be clear in colour.
For part 2 I am not too sure.
2007-02-26 20:11:07 · answer #3 · answered by IIDX Chem 3 · 0⤊ 0⤋
be careful and keep the fire away.
1) just mix it with water
2) check the solutions amount
2007-02-26 21:08:23 · answer #4 · answered by hanibal 5 · 0⤊ 0⤋