How would you solve
Y+6=2x
4x-10y=4
using subsitution
2007-02-26 14:12:27 · 6 answers · asked by straightrider26 1 in Education & Reference ➔ Homework Help
y=2x-6 so 4x-10(2x-6)=4 so 4x-20x-60=4
16x=64
x=4
y=2(4)-6
y=2
2007-02-26 14:16:06 · answer #1 · answered by Vettepilot 5 · 0⤊ 0⤋
Easy man. Just pick a letter from one and plug it into the other one.
I would pick the first one and get y = 2x - 6.
Plug that y into the next one to get 4x - 10(2x-6) = 4.
Solve for x.
4x - 10(2x-6) = 4
4x - 20x - 60 = 4
-16x = 64
x = -4
Now take your new value for x and plug it in the first equation to solve for y. We know that y = 2x - 6 right?
y = 2(-4) - 6
y = -8 - 6
y = -14
Hope this helps!
2007-02-26 22:21:01 · answer #2 · answered by borntofly5303 1 · 0⤊ 0⤋
Y plus 6=2x
Y=8 plus 6=2x
Y=8 plus 6=2 x 2=4 therefore...
it would be 48
4x -10y=4
4xx-10= -40y=4
2007-02-26 22:17:39 · answer #3 · answered by Maka Nani 1 · 0⤊ 0⤋
4x-10(2x-6)=4
(Using the distributive property for 10(2x-6)= 20x-60)
4x-20x-60=4
(4x-20x= -16x) and (60+4=64)
-16x=64
( 64 divided by -16x= -4)
x=-4
y= 2(-4)-6
(2*-4=-8)
y= -8-6
y=-14
2007-02-26 22:42:09 · answer #4 · answered by Anonymous · 0⤊ 0⤋
y=-6+2x
4x-10(-6+2x)=4
4x+60-20x=4
-16x+60=4
-60
-16x=-56
x=3.5
2007-02-26 22:17:39 · answer #5 · answered by Anonymous · 0⤊ 0⤋
the easiest is to just subtract 6 from both sides in the first equation, so you get y=.... then sub that in for y in your second equation. if you can't do the rest, you need to go back to PRE-algebra.
2007-02-26 22:15:36 · answer #6 · answered by stitchfan85 6 · 0⤊ 0⤋